Base | Representation |
---|---|
bin | 100010010111011000100000… |
… | …010111110010100000111011 |
3 | 201211010212220021202220020021 |
4 | 202113120200113302200323 |
5 | 124302241111204101441 |
6 | 1253240543255311311 |
7 | 43556352025025224 |
oct | 4227304027624073 |
9 | 654125807686207 |
10 | 151140442253371 |
11 | 4418133547984a |
12 | 14b5004437b537 |
13 | 664463721040c |
14 | 2947344ad424b |
15 | 127179a6253d1 |
hex | 8976205f283b |
151140442253371 has 2 divisors, whose sum is σ = 151140442253372. Its totient is φ = 151140442253370.
The previous prime is 151140442253347. The next prime is 151140442253407. The reversal of 151140442253371 is 173352244041151.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-151140442253371 is a prime.
It is not a weakly prime, because it can be changed into another prime (151140442223371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75570221126685 + 75570221126686.
It is an arithmetic number, because the mean of its divisors is an integer number (75570221126686).
Almost surely, 2151140442253371 is an apocalyptic number.
151140442253371 is a deficient number, since it is larger than the sum of its proper divisors (1).
151140442253371 is an equidigital number, since it uses as much as digits as its factorization.
151140442253371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403200, while the sum is 43.
The spelling of 151140442253371 in words is "one hundred fifty-one trillion, one hundred forty billion, four hundred forty-two million, two hundred fifty-three thousand, three hundred seventy-one".
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