Base | Representation |
---|---|
bin | 1101101111110000100011… |
… | …1101011110111110111011 |
3 | 1222111220020102100211221211 |
4 | 3123330020331132332323 |
5 | 3440112224401000133 |
6 | 52051201251143551 |
7 | 3116650325254642 |
oct | 333741075367673 |
9 | 58456212324854 |
10 | 15114140250043 |
11 | 48a796416783a |
12 | 184127aba4bb7 |
13 | 858346405183 |
14 | 3a37578ba359 |
15 | 1b3247e87bcd |
hex | dbf08f5efbb |
15114140250043 has 2 divisors, whose sum is σ = 15114140250044. Its totient is φ = 15114140250042.
The previous prime is 15114140250037. The next prime is 15114140250091. The reversal of 15114140250043 is 34005204141151.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15114140250043 - 221 = 15114138152891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15114140249987 and 15114140250014.
It is not a weakly prime, because it can be changed into another prime (15114140254043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7557070125021 + 7557070125022.
It is an arithmetic number, because the mean of its divisors is an integer number (7557070125022).
Almost surely, 215114140250043 is an apocalyptic number.
15114140250043 is a deficient number, since it is larger than the sum of its proper divisors (1).
15114140250043 is an equidigital number, since it uses as much as digits as its factorization.
15114140250043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 15114140250043 its reverse (34005204141151), we get a palindrome (49119344391194).
The spelling of 15114140250043 in words is "fifteen trillion, one hundred fourteen billion, one hundred forty million, two hundred fifty thousand, forty-three".
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