Base | Representation |
---|---|
bin | 1000110011000011000… |
… | …1100000101000011010 |
3 | 112110010100121021000102 |
4 | 2030300301200220122 |
5 | 4434014341443232 |
6 | 153233404335402 |
7 | 13630304665526 |
oct | 2146061405032 |
9 | 473110537012 |
10 | 151142140442 |
11 | 5910a886177 |
12 | 25361244562 |
13 | 11339095cc7 |
14 | 745b33cd86 |
15 | 3de8edb662 |
hex | 2330c60a1a |
151142140442 has 4 divisors (see below), whose sum is σ = 226713210666. Its totient is φ = 75571070220.
The previous prime is 151142140441. The next prime is 151142140459. The reversal of 151142140442 is 244041241151.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 145587270481 + 5554869961 = 381559^2 + 74531^2 .
It is not an unprimeable number, because it can be changed into a prime (151142140441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37785535109 + ... + 37785535112.
Almost surely, 2151142140442 is an apocalyptic number.
151142140442 is a deficient number, since it is larger than the sum of its proper divisors (75571070224).
151142140442 is an equidigital number, since it uses as much as digits as its factorization.
151142140442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75571070223.
The product of its (nonzero) digits is 5120, while the sum is 29.
Adding to 151142140442 its reverse (244041241151), we get a palindrome (395183381593).
The spelling of 151142140442 in words is "one hundred fifty-one billion, one hundred forty-two million, one hundred forty thousand, four hundred forty-two".
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