Base | Representation |
---|---|
bin | 1000110011000011001… |
… | …0100111101011010010 |
3 | 112110010101011001012012 |
4 | 2030300302213223102 |
5 | 4434014430301232 |
6 | 153233414502522 |
7 | 13630310320112 |
oct | 2146062475322 |
9 | 473111131165 |
10 | 151142431442 |
11 | 5910aa64872 |
12 | 25361364a42 |
13 | 113391685b2 |
14 | 745b3b7042 |
15 | 3de90479b2 |
hex | 2330ca7ad2 |
151142431442 has 4 divisors (see below), whose sum is σ = 226713647166. Its totient is φ = 75571215720.
The previous prime is 151142431439. The next prime is 151142431459. The reversal of 151142431442 is 244134241151.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 91082636401 + 60059795041 = 301799^2 + 245071^2 .
It is a junction number, because it is equal to n+sod(n) for n = 151142431399 and 151142431408.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37785607859 + ... + 37785607862.
Almost surely, 2151142431442 is an apocalyptic number.
151142431442 is a deficient number, since it is larger than the sum of its proper divisors (75571215724).
151142431442 is an equidigital number, since it uses as much as digits as its factorization.
151142431442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75571215723.
The product of its digits is 15360, while the sum is 32.
Adding to 151142431442 its reverse (244134241151), we get a palindrome (395276672593).
The spelling of 151142431442 in words is "one hundred fifty-one billion, one hundred forty-two million, four hundred thirty-one thousand, four hundred forty-two".
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