15114353113 has 4 divisors (see below), whose sum is σ = 15115097088. Its totient is φ = 15113609140.

The previous prime is 15114353083. The next prime is 15114353153. The reversal of 15114353113 is 31135341151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31135341151 = 53 ⋅587459267.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15114353113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15114353153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 340633 + ... + 382438.

It is an arithmetic number, because the mean of its divisors is an integer number (3778774272).

Almost surely, 2^15114353113 is an apocalyptic number.

It is an amenable number.

15114353113 is a deficient number, since it is larger than the sum of its proper divisors (743975).

15114353113 is an equidigital number, since it uses as much as digits as its factorization.

15114353113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 743974.

The product of its digits is 2700, while the sum is 28.

Adding to 15114353113 its reverse (31135341151), we get a palindrome (46249694264).

The spelling of 15114353113 in words is "fifteen billion, one hundred fourteen million, three hundred fifty-three thousand, one hundred thirteen".