Base | Representation |
---|---|
bin | 1000110011000101000… |
… | …1111101001110000011 |
3 | 112110010221121101122112 |
4 | 2030301101331032003 |
5 | 4434024031134042 |
6 | 153234310525535 |
7 | 13630440202514 |
oct | 2146121751603 |
9 | 473127541575 |
10 | 151150646147 |
11 | 59114665686 |
12 | 253640668ab |
13 | 1133aa83677 |
14 | 745c514a0b |
15 | 3de9b1b982 |
hex | 233147d383 |
151150646147 has 2 divisors, whose sum is σ = 151150646148. Its totient is φ = 151150646146.
The previous prime is 151150646117. The next prime is 151150646189. The reversal of 151150646147 is 741646051151.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 151150646147 - 230 = 150076904323 is a prime.
It is not a weakly prime, because it can be changed into another prime (151150646107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75575323073 + 75575323074.
It is an arithmetic number, because the mean of its divisors is an integer number (75575323074).
Almost surely, 2151150646147 is an apocalyptic number.
151150646147 is a deficient number, since it is larger than the sum of its proper divisors (1).
151150646147 is an equidigital number, since it uses as much as digits as its factorization.
151150646147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 41.
Adding to 151150646147 its reverse (741646051151), we get a palindrome (892796697298).
The spelling of 151150646147 in words is "one hundred fifty-one billion, one hundred fifty million, six hundred forty-six thousand, one hundred forty-seven".
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