Base | Representation |
---|---|
bin | 1000110011000101000… |
… | …1111111101001110001 |
3 | 112110010221121220022122 |
4 | 2030301101333221301 |
5 | 4434024031443423 |
6 | 153234311044025 |
7 | 13630440243542 |
oct | 2146121775161 |
9 | 473127556278 |
10 | 151150656113 |
11 | 59114672116 |
12 | 25364070615 |
13 | 1133aa88072 |
14 | 745c5184c9 |
15 | 3de9b1e8c8 |
hex | 233147fa71 |
151150656113 has 2 divisors, whose sum is σ = 151150656114. Its totient is φ = 151150656112.
The previous prime is 151150656089. The next prime is 151150656161. The reversal of 151150656113 is 311656051151.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 149434045489 + 1716610624 = 386567^2 + 41432^2 .
It is a cyclic number.
It is not a de Polignac number, because 151150656113 - 224 = 151133878897 is a prime.
It is a super-3 number, since 3×1511506561133 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (151150656913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75575328056 + 75575328057.
It is an arithmetic number, because the mean of its divisors is an integer number (75575328057).
Almost surely, 2151150656113 is an apocalyptic number.
It is an amenable number.
151150656113 is a deficient number, since it is larger than the sum of its proper divisors (1).
151150656113 is an equidigital number, since it uses as much as digits as its factorization.
151150656113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 35.
The spelling of 151150656113 in words is "one hundred fifty-one billion, one hundred fifty million, six hundred fifty-six thousand, one hundred thirteen".
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