Base | Representation |
---|---|
bin | 100010010111101001000100… |
… | …110000111100101001100011 |
3 | 201211012120211010122002120021 |
4 | 202113221010300330221203 |
5 | 124303034030032304233 |
6 | 1253253044454254311 |
7 | 43560551630223136 |
oct | 4227510460745143 |
9 | 654176733562507 |
10 | 151158232697443 |
11 | 44188934741794 |
12 | 14b5358a357397 |
13 | 6646210bbbcba |
14 | 294815177221d |
15 | 1271e8c3d7e2d |
hex | 897a44c3ca63 |
151158232697443 has 2 divisors, whose sum is σ = 151158232697444. Its totient is φ = 151158232697442.
The previous prime is 151158232697429. The next prime is 151158232697489. The reversal of 151158232697443 is 344796232851151.
It is a weak prime.
It is an emirp because it is prime and its reverse (344796232851151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 151158232697443 - 217 = 151158232566371 is a prime.
It is a super-2 number, since 2×1511582326974432 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (151158232697243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75579116348721 + 75579116348722.
It is an arithmetic number, because the mean of its divisors is an integer number (75579116348722).
Almost surely, 2151158232697443 is an apocalyptic number.
151158232697443 is a deficient number, since it is larger than the sum of its proper divisors (1).
151158232697443 is an equidigital number, since it uses as much as digits as its factorization.
151158232697443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 43545600, while the sum is 61.
The spelling of 151158232697443 in words is "one hundred fifty-one trillion, one hundred fifty-eight billion, two hundred thirty-two million, six hundred ninety-seven thousand, four hundred forty-three".
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