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15120025605241 is a prime number
BaseRepresentation
bin1101110000000110011111…
…0000010101010001111001
31222112110102120200212112021
43130001213300111101321
53440211303023331431
652054013250514441
73120246221044624
oct334014760252171
958473376625467
1015120025605241
1148aa404304257
121842441b95a21
13858a7380067b
143a3b553a4dbb
151b348e9c6b11
hexdc067c15479

15120025605241 has 2 divisors, whose sum is σ = 15120025605242. Its totient is φ = 15120025605240.

The previous prime is 15120025605173. The next prime is 15120025605281. The reversal of 15120025605241 is 14250652002151.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14902842576400 + 217183028841 = 3860420^2 + 466029^2 .

It is a cyclic number.

It is not a de Polignac number, because 15120025605241 - 225 = 15119992050809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15120025605197 and 15120025605206.

It is not a weakly prime, because it can be changed into another prime (15120025605281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7560012802620 + 7560012802621.

It is an arithmetic number, because the mean of its divisors is an integer number (7560012802621).

Almost surely, 215120025605241 is an apocalyptic number.

It is an amenable number.

15120025605241 is a deficient number, since it is larger than the sum of its proper divisors (1).

15120025605241 is an equidigital number, since it uses as much as digits as its factorization.

15120025605241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24000, while the sum is 34.

Adding to 15120025605241 its reverse (14250652002151), we get a palindrome (29370677607392).

The spelling of 15120025605241 in words is "fifteen trillion, one hundred twenty billion, twenty-five million, six hundred five thousand, two hundred forty-one".