Base | Representation |
---|---|
bin | 1101110000001010100010… |
… | …0000101011010011110011 |
3 | 1222112120020021222110200202 |
4 | 3130002220200223103303 |
5 | 3440221014134121321 |
6 | 52054313140305415 |
7 | 3120315152320331 |
oct | 334025040532363 |
9 | 58476207873622 |
10 | 15121112020211 |
11 | 48aa91158a96a |
12 | 18426a59a226b |
13 | 858bb7905a72 |
14 | 3a3c197a8b51 |
15 | 1b350507770b |
hex | dc0a882b4f3 |
15121112020211 has 4 divisors (see below), whose sum is σ = 15121124121792. Its totient is φ = 15121099918632.
The previous prime is 15121112020207. The next prime is 15121112020243. The reversal of 15121112020211 is 11202021112151.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 15121112020211 - 22 = 15121112020207 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15121112020811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3928355 + ... + 6758268.
It is an arithmetic number, because the mean of its divisors is an integer number (3780281030448).
Almost surely, 215121112020211 is an apocalyptic number.
15121112020211 is a deficient number, since it is larger than the sum of its proper divisors (12101581).
15121112020211 is a wasteful number, since it uses less digits than its factorization.
15121112020211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12101580.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 15121112020211 its reverse (11202021112151), we get a palindrome (26323133132362).
The spelling of 15121112020211 in words is "fifteen trillion, one hundred twenty-one billion, one hundred twelve million, twenty thousand, two hundred eleven".
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