151311104017 has 2 divisors, whose sum is σ = 151311104018. Its totient is φ = 151311104016.

The previous prime is 151311104011. The next prime is 151311104041. The reversal of 151311104017 is 710401113151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112896672001 + 38414432016 = 336001^2 + 195996^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-151311104017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 151311103982 and 151311104000.

It is not a weakly prime, because it can be changed into another prime (151311104011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75655552008 + 75655552009.

It is an arithmetic number, because the mean of its divisors is an integer number (75655552009).

Almost surely, 2^151311104017 is an apocalyptic number.

It is an amenable number.

151311104017 is a deficient number, since it is larger than the sum of its proper divisors (1).

151311104017 is an equidigital number, since it uses as much as digits as its factorization.

151311104017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420, while the sum is 25.

Adding to 151311104017 its reverse (710401113151), we get a palindrome (861712217168).

The spelling of 151311104017 in words is "one hundred fifty-one billion, three hundred eleven million, one hundred four thousand, seventeen".