15131311122041 has 4 divisors (see below), whose sum is σ = 15132054805392. Its totient is φ = 15130567438692.

The previous prime is 15131311121981. The next prime is 15131311122079. The reversal of 15131311122041 is 14022111313151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15131311122041 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 15131311122041.

It is not an unprimeable number, because it can be changed into a prime (15131311122541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 371811155 + ... + 371851848.

It is an arithmetic number, because the mean of its divisors is an integer number (3783013701348).

Almost surely, 2^{15131311122041} is an apocalyptic number.

It is an amenable number.

15131311122041 is a deficient number, since it is larger than the sum of its proper divisors (743683351).

15131311122041 is an equidigital number, since it uses as much as digits as its factorization.

15131311122041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 743683350.

The product of its (nonzero) digits is 720, while the sum is 26.

Adding to 15131311122041 its reverse (14022111313151), we get a palindrome (29153422435192).

The spelling of 15131311122041 in words is "fifteen trillion, one hundred thirty-one billion, three hundred eleven million, one hundred twenty-two thousand, forty-one".