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15132433050233 is a prime number
BaseRepresentation
bin1101110000110100101101…
…0010111110101001111001
31222120122110021111101022222
43130031023102332221321
53440412210330101413
652103424353253425
73121165540431632
oct334151322765171
958518407441288
1015132433050233
1149046a0a56324
121844925264275
13859ca01b23b5
143a45b1164889
151b3968dcbb08
hexdc34b4bea79

15132433050233 has 2 divisors, whose sum is σ = 15132433050234. Its totient is φ = 15132433050232.

The previous prime is 15132433050187. The next prime is 15132433050281. The reversal of 15132433050233 is 33205033423151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12161177594944 + 2971255455289 = 3487288^2 + 1723733^2 .

It is a cyclic number.

It is not a de Polignac number, because 15132433050233 - 28 = 15132433049977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15132433050193 and 15132433050202.

It is not a weakly prime, because it can be changed into another prime (15132436050233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7566216525116 + 7566216525117.

It is an arithmetic number, because the mean of its divisors is an integer number (7566216525117).

Almost surely, 215132433050233 is an apocalyptic number.

It is an amenable number.

15132433050233 is a deficient number, since it is larger than the sum of its proper divisors (1).

15132433050233 is an equidigital number, since it uses as much as digits as its factorization.

15132433050233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 35.

Adding to 15132433050233 its reverse (33205033423151), we get a palindrome (48337466473384).

The spelling of 15132433050233 in words is "fifteen trillion, one hundred thirty-two billion, four hundred thirty-three million, fifty thousand, two hundred thirty-three".