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1513321104241 = 3080949119449
BaseRepresentation
bin10110000001011000111…
…101111000001101110001
312100200010221122100101201
4112001120331320031301
5144243240200313431
63115113215131201
7214222336101112
oct26013075701561
95320127570351
101513321104241
11533883347151
12205360213b01
13ac923194ccb
1453360900209
1529571ac8461
hex16058f78371

1513321104241 has 4 divisors (see below), whose sum is σ = 1513370254500. Its totient is φ = 1513271953984.

The previous prime is 1513321104233. The next prime is 1513321104247. The reversal of 1513321104241 is 1424011233151.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1202268390400 + 311052713841 = 1096480^2 + 557721^2 .

It is a cyclic number.

It is not a de Polignac number, because 1513321104241 - 23 = 1513321104233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1513321104247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24528916 + ... + 24590533.

It is an arithmetic number, because the mean of its divisors is an integer number (378342563625).

Almost surely, 21513321104241 is an apocalyptic number.

It is an amenable number.

1513321104241 is a deficient number, since it is larger than the sum of its proper divisors (49150259).

1513321104241 is an equidigital number, since it uses as much as digits as its factorization.

1513321104241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49150258.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 1513321104241 its reverse (1424011233151), we get a palindrome (2937332337392).

The spelling of 1513321104241 in words is "one trillion, five hundred thirteen billion, three hundred twenty-one million, one hundred four thousand, two hundred forty-one".

Divisors: 1 30809 49119449 1513321104241