Base | Representation |
---|---|
bin | 10110000001011001001… |
… | …000111011100110110001 |
3 | 12100200011011002112222111 |
4 | 112001121020323212301 |
5 | 144243241421023323 |
6 | 3115113401205321 |
7 | 214222402526416 |
oct | 26013110734661 |
9 | 5320134075874 |
10 | 1513324001713 |
11 | 533884a46057 |
12 | 205361190841 |
13 | ac92396aaa4 |
14 | 5336105610d |
15 | 29571e9bc0d |
hex | 1605923b9b1 |
1513324001713 has 4 divisors (see below), whose sum is σ = 1513327929328. Its totient is φ = 1513320074100.
The previous prime is 1513324001687. The next prime is 1513324001729. The reversal of 1513324001713 is 3171004233151.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1513324001713 - 25 = 1513324001681 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1513327001713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1314231 + ... + 2180332.
It is an arithmetic number, because the mean of its divisors is an integer number (378331982332).
Almost surely, 21513324001713 is an apocalyptic number.
It is an amenable number.
1513324001713 is a deficient number, since it is larger than the sum of its proper divisors (3927615).
1513324001713 is an equidigital number, since it uses as much as digits as its factorization.
1513324001713 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3927614.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 1513324001713 its reverse (3171004233151), we get a palindrome (4684328234864).
The spelling of 1513324001713 in words is "one trillion, five hundred thirteen billion, three hundred twenty-four million, one thousand, seven hundred thirteen".
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