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1513324001713 = 4330513494563
BaseRepresentation
bin10110000001011001001…
…000111011100110110001
312100200011011002112222111
4112001121020323212301
5144243241421023323
63115113401205321
7214222402526416
oct26013110734661
95320134075874
101513324001713
11533884a46057
12205361190841
13ac92396aaa4
145336105610d
1529571e9bc0d
hex1605923b9b1

1513324001713 has 4 divisors (see below), whose sum is σ = 1513327929328. Its totient is φ = 1513320074100.

The previous prime is 1513324001687. The next prime is 1513324001729. The reversal of 1513324001713 is 3171004233151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1513324001713 - 25 = 1513324001681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1513327001713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1314231 + ... + 2180332.

It is an arithmetic number, because the mean of its divisors is an integer number (378331982332).

Almost surely, 21513324001713 is an apocalyptic number.

It is an amenable number.

1513324001713 is a deficient number, since it is larger than the sum of its proper divisors (3927615).

1513324001713 is an equidigital number, since it uses as much as digits as its factorization.

1513324001713 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3927614.

The product of its (nonzero) digits is 7560, while the sum is 31.

Adding to 1513324001713 its reverse (3171004233151), we get a palindrome (4684328234864).

The spelling of 1513324001713 in words is "one trillion, five hundred thirteen billion, three hundred twenty-four million, one thousand, seven hundred thirteen".

Divisors: 1 433051 3494563 1513324001713