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15140153153137 is a prime number
BaseRepresentation
bin1101110001010001011101…
…1100110101011001110001
31222121101101022020020121011
43130110113130311121301
53441024013201400022
652111142414030521
73121561052300365
oct334242734653161
958541338206534
1015140153153137
1149079a282a961
12184631a7a8441
1385a93074591c
143a4b045ad2a5
151b3c6ba39977
hexdc517735671

15140153153137 has 2 divisors, whose sum is σ = 15140153153138. Its totient is φ = 15140153153136.

The previous prime is 15140153153129. The next prime is 15140153153239. The reversal of 15140153153137 is 73135135104151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14338915128976 + 801238024161 = 3786676^2 + 895119^2 .

It is a cyclic number.

It is not a de Polignac number, because 15140153153137 - 23 = 15140153153129 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 15140153153137.

It is not a weakly prime, because it can be changed into another prime (15140153153737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7570076576568 + 7570076576569.

It is an arithmetic number, because the mean of its divisors is an integer number (7570076576569).

Almost surely, 215140153153137 is an apocalyptic number.

It is an amenable number.

15140153153137 is a deficient number, since it is larger than the sum of its proper divisors (1).

15140153153137 is an equidigital number, since it uses as much as digits as its factorization.

15140153153137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 94500, while the sum is 40.

Adding to 15140153153137 its reverse (73135135104151), we get a palindrome (88275288257288).

The spelling of 15140153153137 in words is "fifteen trillion, one hundred forty billion, one hundred fifty-three million, one hundred fifty-three thousand, one hundred thirty-seven".