Base | Representation |
---|---|
bin | 1000110100100111111… |
… | …1010111000001001011 |
3 | 112111012211122222122212 |
4 | 2031021333113001023 |
5 | 4440401142421413 |
6 | 153343400135335 |
7 | 13643632645613 |
oct | 2151177270113 |
9 | 474184588585 |
10 | 151565201483 |
11 | 593076721a3 |
12 | 2545aa6754b |
13 | 113a5920097 |
14 | 749b5c7a43 |
15 | 3e21207ca8 |
hex | 2349fd704b |
151565201483 has 2 divisors, whose sum is σ = 151565201484. Its totient is φ = 151565201482.
The previous prime is 151565201423. The next prime is 151565201507. The reversal of 151565201483 is 384102565151.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 151565201483 - 26 = 151565201419 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 151565201483.
It is not a weakly prime, because it can be changed into another prime (151565201423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75782600741 + 75782600742.
It is an arithmetic number, because the mean of its divisors is an integer number (75782600742).
Almost surely, 2151565201483 is an apocalyptic number.
151565201483 is a deficient number, since it is larger than the sum of its proper divisors (1).
151565201483 is an equidigital number, since it uses as much as digits as its factorization.
151565201483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 41.
The spelling of 151565201483 in words is "one hundred fifty-one billion, five hundred sixty-five million, two hundred one thousand, four hundred eighty-three".
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