Base | Representation |
---|---|
bin | 100010011111100110011010… |
… | …000111111101101101011011 |
3 | 201220010212110001012011022222 |
4 | 202133212122013331231123 |
5 | 124341014044131003201 |
6 | 1254352212252134255 |
7 | 43645222302441023 |
oct | 4237463207755533 |
9 | 656125401164288 |
10 | 151705125641051 |
11 | 44379867530834 |
12 | 1502157776738b |
13 | 6685969180988 |
14 | 29667d27b2a83 |
15 | 12812e9c2191b |
hex | 89f99a1fdb5b |
151705125641051 has 2 divisors, whose sum is σ = 151705125641052. Its totient is φ = 151705125641050.
The previous prime is 151705125641039. The next prime is 151705125641093. The reversal of 151705125641051 is 150146521507151.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-151705125641051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 151705125640993 and 151705125641011.
It is not a weakly prime, because it can be changed into another prime (151705125647051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75852562820525 + 75852562820526.
It is an arithmetic number, because the mean of its divisors is an integer number (75852562820526).
Almost surely, 2151705125641051 is an apocalyptic number.
151705125641051 is a deficient number, since it is larger than the sum of its proper divisors (1).
151705125641051 is an equidigital number, since it uses as much as digits as its factorization.
151705125641051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 210000, while the sum is 44.
The spelling of 151705125641051 in words is "one hundred fifty-one trillion, seven hundred five billion, one hundred twenty-five million, six hundred forty-one thousand, fifty-one".
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