Search a number
-
+
151787000843 is a prime number
BaseRepresentation
bin1000110101011100110…
…1011101010000001011
3112111210022000120011222
42031113031131100023
54441324433011333
6153421402112255
713652265135152
oct2152715352013
9474708016158
10151787000843
1159410894355
12255011ab68b
131140c86a7ca
1474bcc42599
153e3591b298
hex235735d40b

151787000843 has 2 divisors, whose sum is σ = 151787000844. Its totient is φ = 151787000842.

The previous prime is 151787000693. The next prime is 151787000857. The reversal of 151787000843 is 348000787151.

151787000843 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (348000787151) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-151787000843 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 151787000794 and 151787000803.

It is not a weakly prime, because it can be changed into another prime (151787000863) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75893500421 + 75893500422.

It is an arithmetic number, because the mean of its divisors is an integer number (75893500422).

Almost surely, 2151787000843 is an apocalyptic number.

151787000843 is a deficient number, since it is larger than the sum of its proper divisors (1).

151787000843 is an equidigital number, since it uses as much as digits as its factorization.

151787000843 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 188160, while the sum is 44.

Adding to 151787000843 its reverse (348000787151), we get a palindrome (499787787994).

The spelling of 151787000843 in words is "one hundred fifty-one billion, seven hundred eighty-seven million, eight hundred forty-three", and thus it is an aban number.