Search a number
-
+
1520214497 is a prime number
BaseRepresentation
bin101101010011100…
…1010000111100001
310220221112220020122
41122213022013201
511103133330442
6410503250025
752446416144
oct13247120741
93827486218
101520214497
1171013771a
12365149915
131b2c4c209
14105c8605b
158d6dddd2
hex5a9ca1e1

1520214497 has 2 divisors, whose sum is σ = 1520214498. Its totient is φ = 1520214496.

The previous prime is 1520214461. The next prime is 1520214517. The reversal of 1520214497 is 7944120251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 984014161 + 536200336 = 31369^2 + 23156^2 .

It is a cyclic number.

It is not a de Polignac number, because 1520214497 - 216 = 1520148961 is a prime.

It is a super-2 number, since 2×15202144972 = 4622104233777926018, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1520214457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 760107248 + 760107249.

It is an arithmetic number, because the mean of its divisors is an integer number (760107249).

Almost surely, 21520214497 is an apocalyptic number.

It is an amenable number.

1520214497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1520214497 is an equidigital number, since it uses as much as digits as its factorization.

1520214497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 35.

The square root of 1520214497 is about 38989.9281481769. The cubic root of 1520214497 is about 1149.8334975072.

The spelling of 1520214497 in words is "one billion, five hundred twenty million, two hundred fourteen thousand, four hundred ninety-seven".