Base | Representation |
---|---|
bin | 10110000111111111101… |
… | …000110000111111100001 |
3 | 12101100110011001001010220 |
4 | 112013333220300333201 |
5 | 144402301024111001 |
6 | 3122245012513253 |
7 | 214563143405403 |
oct | 26077750607741 |
9 | 5340404031126 |
10 | 1520412332001 |
11 | 536892140562 |
12 | 2067bb01b829 |
13 | b04b335c974 |
14 | 53834606b73 |
15 | 29839412c36 |
hex | 161ffa30fe1 |
1520412332001 has 4 divisors (see below), whose sum is σ = 2027216442672. Its totient is φ = 1013608221332.
The previous prime is 1520412331951. The next prime is 1520412332003. The reversal of 1520412332001 is 1002332140251.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1520412332001 - 27 = 1520412331873 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1520412332003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253402055331 + ... + 253402055336.
It is an arithmetic number, because the mean of its divisors is an integer number (506804110668).
Almost surely, 21520412332001 is an apocalyptic number.
It is an amenable number.
1520412332001 is a deficient number, since it is larger than the sum of its proper divisors (506804110671).
1520412332001 is an equidigital number, since it uses as much as digits as its factorization.
1520412332001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 506804110670.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 1520412332001 its reverse (1002332140251), we get a palindrome (2522744472252).
The spelling of 1520412332001 in words is "one trillion, five hundred twenty billion, four hundred twelve million, three hundred thirty-two thousand, one".
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