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1521132421139 is a prime number
BaseRepresentation
bin10110001000101010100…
…011101100000000010011
312101102022100000100201222
4112020222203230000103
5144410234344434024
63122444254515255
7214620036146552
oct26105243540023
95342270010658
101521132421139
11537121661151
12206980205b2b
13b05995b3c06
14538a20cdd99
152987c75285e
hex1622a8ec013

1521132421139 has 2 divisors, whose sum is σ = 1521132421140. Its totient is φ = 1521132421138.

The previous prime is 1521132421111. The next prime is 1521132421157. The reversal of 1521132421139 is 9311242311251.

It is a strong prime.

It is an emirp because it is prime and its reverse (9311242311251) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1521132421139 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1521132421099 and 1521132421108.

It is not a weakly prime, because it can be changed into another prime (1521132421199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 760566210569 + 760566210570.

It is an arithmetic number, because the mean of its divisors is an integer number (760566210570).

Almost surely, 21521132421139 is an apocalyptic number.

1521132421139 is a deficient number, since it is larger than the sum of its proper divisors (1).

1521132421139 is an equidigital number, since it uses as much as digits as its factorization.

1521132421139 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12960, while the sum is 35.

The spelling of 1521132421139 in words is "one trillion, five hundred twenty-one billion, one hundred thirty-two million, four hundred twenty-one thousand, one hundred thirty-nine".