Base | Representation |
---|---|
bin | 1000110110101011000… |
… | …1000011101000110011 |
3 | 112112122011101201220102 |
4 | 2031222301003220303 |
5 | 4443012431201321 |
6 | 153514122303015 |
7 | 13663361006114 |
oct | 2155261035063 |
9 | 475564351812 |
10 | 152115100211 |
11 | 5956a010258 |
12 | 25593057a6b |
13 | 11462826449 |
14 | 751064c20b |
15 | 3e5462ac0b |
hex | 236ac43a33 |
152115100211 has 2 divisors, whose sum is σ = 152115100212. Its totient is φ = 152115100210.
The previous prime is 152115100169. The next prime is 152115100217. The reversal of 152115100211 is 112001511251.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 152115100211 - 26 = 152115100147 is a prime.
It is not a weakly prime, because it can be changed into another prime (152115100217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76057550105 + 76057550106.
It is an arithmetic number, because the mean of its divisors is an integer number (76057550106).
Almost surely, 2152115100211 is an apocalyptic number.
152115100211 is a deficient number, since it is larger than the sum of its proper divisors (1).
152115100211 is an equidigital number, since it uses as much as digits as its factorization.
152115100211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100, while the sum is 20.
Adding to 152115100211 its reverse (112001511251), we get a palindrome (264116611462).
The spelling of 152115100211 in words is "one hundred fifty-two billion, one hundred fifteen million, one hundred thousand, two hundred eleven".
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