Base | Representation |
---|---|
bin | 10010001000100… |
… | …01110100111001 |
3 | 101121020022122211 |
4 | 21010101310321 |
5 | 302420212122 |
6 | 23032215121 |
7 | 3524653306 |
oct | 1104216471 |
9 | 347208584 |
10 | 152116537 |
11 | 78958451 |
12 | 42b3a4a1 |
13 | 256903b1 |
14 | 162ba0ad |
15 | d54b877 |
hex | 9111d39 |
152116537 has 2 divisors, whose sum is σ = 152116538. Its totient is φ = 152116536.
The previous prime is 152116511. The next prime is 152116553. The reversal of 152116537 is 735611251.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 143496441 + 8620096 = 11979^2 + 2936^2 .
It is an emirp because it is prime and its reverse (735611251) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-152116537 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 152116499 and 152116508.
It is not a weakly prime, because it can be changed into another prime (152116637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76058268 + 76058269.
It is an arithmetic number, because the mean of its divisors is an integer number (76058269).
Almost surely, 2152116537 is an apocalyptic number.
It is an amenable number.
152116537 is a deficient number, since it is larger than the sum of its proper divisors (1).
152116537 is an equidigital number, since it uses as much as digits as its factorization.
152116537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6300, while the sum is 31.
The square root of 152116537 is about 12333.5532998402. The cubic root of 152116537 is about 533.8166841675.
Adding to 152116537 its reverse (735611251), we get a palindrome (887727788).
The spelling of 152116537 in words is "one hundred fifty-two million, one hundred sixteen thousand, five hundred thirty-seven".
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