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152121102113 = 239636489967
BaseRepresentation
bin1000110110101100011…
…1111100111100100001
3112112122120200122222002
42031223013330330201
54443021000231423
6153514455053345
713663463014301
oct2155307747441
9475576618862
10152121102113
115957243a602
1225595071255
1311463b48276
147511371601
153e54e14228
hex236b1fcf21

152121102113 has 4 divisors (see below), whose sum is σ = 152757592320. Its totient is φ = 151484611908.

The previous prime is 152121102053. The next prime is 152121102229. The reversal of 152121102113 is 311201121251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 152121102113 - 226 = 152053993249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (152121102313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318244745 + ... + 318245222.

It is an arithmetic number, because the mean of its divisors is an integer number (38189398080).

Almost surely, 2152121102113 is an apocalyptic number.

It is an amenable number.

152121102113 is a deficient number, since it is larger than the sum of its proper divisors (636490207).

152121102113 is an equidigital number, since it uses as much as digits as its factorization.

152121102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 636490206.

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 152121102113 its reverse (311201121251), we get a palindrome (463322223364).

The spelling of 152121102113 in words is "one hundred fifty-two billion, one hundred twenty-one million, one hundred two thousand, one hundred thirteen".

Divisors: 1 239 636489967 152121102113