Base | Representation |
---|---|
bin | 1101110101100000111110… |
… | …0110111111001110010011 |
3 | 1222212100111122020120022021 |
4 | 3131120033212333032103 |
5 | 3443222244211303412 |
6 | 52204434451152311 |
7 | 3130051133520262 |
oct | 335301746771623 |
9 | 58770448216267 |
10 | 15213036041107 |
11 | 49358a3273373 |
12 | 185847aba5697 |
13 | 86477721c238 |
14 | 3a845a0245d9 |
15 | 1b5ad52a9607 |
hex | dd60f9bf393 |
15213036041107 has 4 divisors (see below), whose sum is σ = 15214338873376. Its totient is φ = 15211733208840.
The previous prime is 15213036041041. The next prime is 15213036041141. The reversal of 15213036041107 is 70114063031251.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 15213036041107 - 211 = 15213036039059 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15213036041407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 651398619 + ... + 651421972.
It is an arithmetic number, because the mean of its divisors is an integer number (3803584718344).
Almost surely, 215213036041107 is an apocalyptic number.
15213036041107 is a deficient number, since it is larger than the sum of its proper divisors (1302832269).
15213036041107 is a wasteful number, since it uses less digits than its factorization.
15213036041107 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1302832268.
The product of its (nonzero) digits is 15120, while the sum is 34.
Adding to 15213036041107 its reverse (70114063031251), we get a palindrome (85327099072358).
The spelling of 15213036041107 in words is "fifteen trillion, two hundred thirteen billion, thirty-six million, forty-one thousand, one hundred seven".
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