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15220113 = 35073371
BaseRepresentation
bin111010000011…
…110110010001
31001122021001220
4322003312101
512344020423
61302115253
7243240336
oct72036621
931567056
1015220113
118656107
12511bb29
1331cb8ac
14204298d
1515099e3
hexe83d91

15220113 has 4 divisors (see below), whose sum is σ = 20293488. Its totient is φ = 10146740.

The previous prime is 15220111. The next prime is 15220129. The reversal of 15220113 is 31102251.

15220113 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15220113 - 21 = 15220111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15220092 and 15220101.

It is not an unprimeable number, because it can be changed into a prime (15220111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2536683 + ... + 2536688.

It is an arithmetic number, because the mean of its divisors is an integer number (5073372).

Almost surely, 215220113 is an apocalyptic number.

It is an amenable number.

15220113 is a deficient number, since it is larger than the sum of its proper divisors (5073375).

15220113 is an equidigital number, since it uses as much as digits as its factorization.

15220113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5073374.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 15220113 is about 3901.2963230188. The cubic root of 15220113 is about 247.8216774370.

Adding to 15220113 its reverse (31102251), we get a palindrome (46322364).

The spelling of 15220113 in words is "fifteen million, two hundred twenty thousand, one hundred thirteen".

Divisors: 1 3 5073371 15220113