Base | Representation |
---|---|
bin | 1000110111000000100… |
… | …0011010101101110011 |
3 | 112112212102202201022011 |
4 | 2031300020122231303 |
5 | 4443204002011011 |
6 | 153531055423351 |
7 | 13665533042524 |
oct | 2156010325563 |
9 | 475772681264 |
10 | 152205110131 |
11 | 596058a9018 |
12 | 255b9224b57 |
13 | 1147837ca59 |
14 | 751c59c84b |
15 | 3e5c4aa621 |
hex | 237021ab73 |
152205110131 has 4 divisors (see below), whose sum is σ = 152515100664. Its totient is φ = 151895119600.
The previous prime is 152205110129. The next prime is 152205110177. The reversal of 152205110131 is 131011502251.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 152205110131 - 21 = 152205110129 is a prime.
It is a super-2 number, since 2×1522051101312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (152205110731) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154994530 + ... + 154995511.
It is an arithmetic number, because the mean of its divisors is an integer number (38128775166).
Almost surely, 2152205110131 is an apocalyptic number.
152205110131 is a deficient number, since it is larger than the sum of its proper divisors (309990533).
152205110131 is an equidigital number, since it uses as much as digits as its factorization.
152205110131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 309990532.
The product of its (nonzero) digits is 300, while the sum is 22.
Adding to 152205110131 its reverse (131011502251), we get a palindrome (283216612382).
The spelling of 152205110131 in words is "one hundred fifty-two billion, two hundred five million, one hundred ten thousand, one hundred thirty-one".
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