Search a number
-
+
15225001201 = 31491129071
BaseRepresentation
bin11100010110111101…
…10001010011110001
31110022001112012022101
432023132301103301
5222140100014301
610554432340401
71046201242414
oct161336612361
943261465271
1015225001201
116503130823
122b4a9a4701
131588347c67
14a46073b7b
155e195b701
hex38b7b14f1

15225001201 has 4 divisors (see below), whose sum is σ = 15716130304. Its totient is φ = 14733872100.

The previous prime is 15225001193. The next prime is 15225001241. The reversal of 15225001201 is 10210052251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10210052251 = 71458578893.

It is a cyclic number.

It is not a de Polignac number, because 15225001201 - 23 = 15225001193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15225001241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245564505 + ... + 245564566.

It is an arithmetic number, because the mean of its divisors is an integer number (3929032576).

Almost surely, 215225001201 is an apocalyptic number.

It is an amenable number.

15225001201 is a deficient number, since it is larger than the sum of its proper divisors (491129103).

15225001201 is an equidigital number, since it uses as much as digits as its factorization.

15225001201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 491129102.

The product of its (nonzero) digits is 200, while the sum is 19.

Adding to 15225001201 its reverse (10210052251), we get a palindrome (25435053452).

The spelling of 15225001201 in words is "fifteen billion, two hundred twenty-five million, one thousand, two hundred one".

Divisors: 1 31 491129071 15225001201