Base | Representation |
---|---|
bin | 100010100111100100110001… |
… | …001101101101001000111011 |
3 | 201222002020220210210121211211 |
4 | 202213210301031231020323 |
5 | 124424003343031233001 |
6 | 1255452041322103551 |
7 | 44032632165226513 |
oct | 4247446115551073 |
9 | 658066823717754 |
10 | 152253121352251 |
11 | 44570205855457 |
12 | 150ab81234abb7 |
13 | 66c553ba51c5a |
14 | 298513a072843 |
15 | 12906be28b351 |
hex | 8a793136d23b |
152253121352251 has 2 divisors, whose sum is σ = 152253121352252. Its totient is φ = 152253121352250.
The previous prime is 152253121352207. The next prime is 152253121352287.
152253121352251 is nontrivially palindromic in base 10.
152253121352251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 152253121352251 - 245 = 117068749263419 is a prime.
It is not a weakly prime, because it can be changed into another prime (152253121356251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76126560676125 + 76126560676126.
It is an arithmetic number, because the mean of its divisors is an integer number (76126560676126).
Almost surely, 2152253121352251 is an apocalyptic number.
152253121352251 is a deficient number, since it is larger than the sum of its proper divisors (1).
152253121352251 is an equidigital number, since it uses as much as digits as its factorization.
152253121352251 is an evil number, because the sum of its binary digits is even.
The product of its digits is 180000, while the sum is 40.
The spelling of 152253121352251 in words is "one hundred fifty-two trillion, two hundred fifty-three billion, one hundred twenty-one million, three hundred fifty-two thousand, two hundred fifty-one".
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