Base | Representation |
---|---|
bin | 1000110111010111011… |
… | …0011001110101101001 |
3 | 112120010010022000202121 |
4 | 2031311312121311221 |
5 | 4443403032114431 |
6 | 153544404031241 |
7 | 14001106401313 |
oct | 2156566316551 |
9 | 476103260677 |
10 | 152301051241 |
11 | 59654a77a99 |
12 | 25625392521 |
13 | 11492201c41 |
14 | 752b2147b3 |
15 | 3e65b0c611 |
hex | 2375d99d69 |
152301051241 has 2 divisors, whose sum is σ = 152301051242. Its totient is φ = 152301051240.
The previous prime is 152301051233. The next prime is 152301051269. The reversal of 152301051241 is 142150103251.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 108464835600 + 43836215641 = 329340^2 + 209371^2 .
It is a cyclic number.
It is not a de Polignac number, because 152301051241 - 23 = 152301051233 is a prime.
It is a super-2 number, since 2×1523010512412 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (152301021241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76150525620 + 76150525621.
It is an arithmetic number, because the mean of its divisors is an integer number (76150525621).
Almost surely, 2152301051241 is an apocalyptic number.
It is an amenable number.
152301051241 is a deficient number, since it is larger than the sum of its proper divisors (1).
152301051241 is an equidigital number, since it uses as much as digits as its factorization.
152301051241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 152301051241 its reverse (142150103251), we get a palindrome (294451154492).
The spelling of 152301051241 in words is "one hundred fifty-two billion, three hundred one million, fifty-one thousand, two hundred forty-one".
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