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152301051241 is a prime number
BaseRepresentation
bin1000110111010111011…
…0011001110101101001
3112120010010022000202121
42031311312121311221
54443403032114431
6153544404031241
714001106401313
oct2156566316551
9476103260677
10152301051241
1159654a77a99
1225625392521
1311492201c41
14752b2147b3
153e65b0c611
hex2375d99d69

152301051241 has 2 divisors, whose sum is σ = 152301051242. Its totient is φ = 152301051240.

The previous prime is 152301051233. The next prime is 152301051269. The reversal of 152301051241 is 142150103251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108464835600 + 43836215641 = 329340^2 + 209371^2 .

It is a cyclic number.

It is not a de Polignac number, because 152301051241 - 23 = 152301051233 is a prime.

It is a super-2 number, since 2×1523010512412 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (152301021241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76150525620 + 76150525621.

It is an arithmetic number, because the mean of its divisors is an integer number (76150525621).

Almost surely, 2152301051241 is an apocalyptic number.

It is an amenable number.

152301051241 is a deficient number, since it is larger than the sum of its proper divisors (1).

152301051241 is an equidigital number, since it uses as much as digits as its factorization.

152301051241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 152301051241 its reverse (142150103251), we get a palindrome (294451154492).

The spelling of 152301051241 in words is "one hundred fifty-two billion, three hundred one million, fifty-one thousand, two hundred forty-one".