Base | Representation |
---|---|
bin | 100010101000100111101110… |
… | …010011101110111100000001 |
3 | 201222100010111002012010021220 |
4 | 202220213232103232330001 |
5 | 124431143111401144131 |
6 | 1255545051200105253 |
7 | 44041055554562625 |
oct | 4250475623567401 |
9 | 658303432163256 |
10 | 152325013303041 |
11 | 445987479a5117 |
12 | 15101736905229 |
13 | 66cc2581424c7 |
14 | 29887da059185 |
15 | 12924caa19e96 |
hex | 8a89ee4eef01 |
152325013303041 has 4 divisors (see below), whose sum is σ = 203100017737392. Its totient is φ = 101550008868692.
The previous prime is 152325013302989. The next prime is 152325013303069. The reversal of 152325013303041 is 140303310523251.
152325013303041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 152325013303041 - 210 = 152325013302017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 152325013302993 and 152325013303011.
It is not an unprimeable number, because it can be changed into a prime (152325013304041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25387502217171 + ... + 25387502217176.
It is an arithmetic number, because the mean of its divisors is an integer number (50775004434348).
Almost surely, 2152325013303041 is an apocalyptic number.
It is an amenable number.
152325013303041 is a deficient number, since it is larger than the sum of its proper divisors (50775004434351).
152325013303041 is an equidigital number, since it uses as much as digits as its factorization.
152325013303041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50775004434350.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 152325013303041 its reverse (140303310523251), we get a palindrome (292628323826292).
The spelling of 152325013303041 in words is "one hundred fifty-two trillion, three hundred twenty-five billion, thirteen million, three hundred three thousand, forty-one".
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