Base | Representation |
---|---|
bin | 1000110111100011110… |
… | …1111000101000000001 |
3 | 112120020202200202221111 |
4 | 2031320331320220001 |
5 | 4444004424002001 |
6 | 153553512523321 |
7 | 14002313025325 |
oct | 2157075705001 |
9 | 476222622844 |
10 | 152353344001 |
11 | 59681544351 |
12 | 2563a9b0541 |
13 | 1149ccb0ac1 |
14 | 7534147985 |
15 | 3e6a4db851 |
hex | 2378f78a01 |
152353344001 has 4 divisors (see below), whose sum is σ = 152558396352. Its totient is φ = 152148291652.
The previous prime is 152353343981. The next prime is 152353344019. The reversal of 152353344001 is 100443353251.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 152353344001 - 227 = 152219126273 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (152353341001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102525061 + ... + 102526546.
It is an arithmetic number, because the mean of its divisors is an integer number (38139599088).
Almost surely, 2152353344001 is an apocalyptic number.
It is an amenable number.
152353344001 is a deficient number, since it is larger than the sum of its proper divisors (205052351).
152353344001 is an equidigital number, since it uses as much as digits as its factorization.
152353344001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 205052350.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 152353344001 its reverse (100443353251), we get a palindrome (252796697252).
The spelling of 152353344001 in words is "one hundred fifty-two billion, three hundred fifty-three million, three hundred forty-four thousand, one".
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