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15243401552441 is a prime number
BaseRepresentation
bin1101110111010010000110…
…0010001110001000111001
31222222020212212022100222012
43131310201202032020321
53444221441244134231
652230415541335305
73132204462225656
oct335644142161071
958866785270865
1015243401552441
114947765866487
121862334407535
138675a623b81a
143a9adac16c2d
151b67b1032e2b
hexddd2188e239

15243401552441 has 2 divisors, whose sum is σ = 15243401552442. Its totient is φ = 15243401552440.

The previous prime is 15243401552419. The next prime is 15243401552459. The reversal of 15243401552441 is 14425510434251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12180100000000 + 3063301552441 = 3490000^2 + 1750229^2 .

It is a cyclic number.

It is not a de Polignac number, because 15243401552441 - 226 = 15243334443577 is a prime.

It is a super-2 number, since 2×152434015524412 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15243401552641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7621700776220 + 7621700776221.

It is an arithmetic number, because the mean of its divisors is an integer number (7621700776221).

Almost surely, 215243401552441 is an apocalyptic number.

It is an amenable number.

15243401552441 is a deficient number, since it is larger than the sum of its proper divisors (1).

15243401552441 is an equidigital number, since it uses as much as digits as its factorization.

15243401552441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384000, while the sum is 41.

Adding to 15243401552441 its reverse (14425510434251), we get a palindrome (29668911986692).

The spelling of 15243401552441 in words is "fifteen trillion, two hundred forty-three billion, four hundred one million, five hundred fifty-two thousand, four hundred forty-one".