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152442422230531 is a prime number
BaseRepresentation
bin100010101010010101000100…
…011011001111111000000011
3201222202100112111210121111211
4202222111010123033320003
5124440104040042334111
61300115025412550551
744052413222156026
oct4252250433177003
9658670474717454
10152442422230531
11446335172020a4
1215120442922457
13670a349591274
1429903772051bd
15129559d2a5521
hex8aa5446cfe03

152442422230531 has 2 divisors, whose sum is σ = 152442422230532. Its totient is φ = 152442422230530.

The previous prime is 152442422230459. The next prime is 152442422230537. The reversal of 152442422230531 is 135032224244251.

It is a strong prime.

It is an emirp because it is prime and its reverse (135032224244251) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 152442422230531 - 221 = 152442420133379 is a prime.

It is a super-2 number, since 2×1524424222305312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (152442422230537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76221211115265 + 76221211115266.

It is an arithmetic number, because the mean of its divisors is an integer number (76221211115266).

Almost surely, 2152442422230531 is an apocalyptic number.

152442422230531 is a deficient number, since it is larger than the sum of its proper divisors (1).

152442422230531 is an equidigital number, since it uses as much as digits as its factorization.

152442422230531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 460800, while the sum is 40.

Adding to 152442422230531 its reverse (135032224244251), we get a palindrome (287474646474782).

The spelling of 152442422230531 in words is "one hundred fifty-two trillion, four hundred forty-two billion, four hundred twenty-two million, two hundred thirty thousand, five hundred thirty-one".