Base | Representation |
---|---|
bin | 100010101010010101000100… |
… | …011011001111111000000011 |
3 | 201222202100112111210121111211 |
4 | 202222111010123033320003 |
5 | 124440104040042334111 |
6 | 1300115025412550551 |
7 | 44052413222156026 |
oct | 4252250433177003 |
9 | 658670474717454 |
10 | 152442422230531 |
11 | 446335172020a4 |
12 | 15120442922457 |
13 | 670a349591274 |
14 | 29903772051bd |
15 | 129559d2a5521 |
hex | 8aa5446cfe03 |
152442422230531 has 2 divisors, whose sum is σ = 152442422230532. Its totient is φ = 152442422230530.
The previous prime is 152442422230459. The next prime is 152442422230537. The reversal of 152442422230531 is 135032224244251.
It is a strong prime.
It is an emirp because it is prime and its reverse (135032224244251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 152442422230531 - 221 = 152442420133379 is a prime.
It is a super-2 number, since 2×1524424222305312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (152442422230537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76221211115265 + 76221211115266.
It is an arithmetic number, because the mean of its divisors is an integer number (76221211115266).
Almost surely, 2152442422230531 is an apocalyptic number.
152442422230531 is a deficient number, since it is larger than the sum of its proper divisors (1).
152442422230531 is an equidigital number, since it uses as much as digits as its factorization.
152442422230531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 152442422230531 its reverse (135032224244251), we get a palindrome (287474646474782).
The spelling of 152442422230531 in words is "one hundred fifty-two trillion, four hundred forty-two billion, four hundred twenty-two million, two hundred thirty thousand, five hundred thirty-one".
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