Search a number
-
+
15245250131 = 27743549517
BaseRepresentation
bin11100011001011000…
…00000111001010011
31110100110121221121202
432030230000321103
5222210241001011
611000434341415
71046535326246
oct161454007123
943313557552
1015245250131
116513601081
122b5572a86b
13158c5b7787
14a48a2525d
155e360b23b
hex38cb00e53

15245250131 has 4 divisors (see below), whose sum is σ = 15245827392. Its totient is φ = 15244672872.

The previous prime is 15245250121. The next prime is 15245250161. The reversal of 15245250131 is 13105254251.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 15245250131 - 214 = 15245233747 is a prime.

It is a super-2 number, since 2×152452501312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15245250094 and 15245250103.

It is not an unprimeable number, because it can be changed into a prime (15245250121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 247016 + ... + 302501.

It is an arithmetic number, because the mean of its divisors is an integer number (3811456848).

Almost surely, 215245250131 is an apocalyptic number.

15245250131 is a deficient number, since it is larger than the sum of its proper divisors (577261).

15245250131 is an equidigital number, since it uses as much as digits as its factorization.

15245250131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 577260.

The product of its (nonzero) digits is 6000, while the sum is 29.

The spelling of 15245250131 in words is "fifteen billion, two hundred forty-five million, two hundred fifty thousand, one hundred thirty-one".

Divisors: 1 27743 549517 15245250131