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1525143320017 is a prime number
BaseRepresentation
bin10110001100011001101…
…000000011010111010001
312101210122212020010122021
4112030121220003113101
5144441443142220032
63124350254211441
7215121321215362
oct26143150032721
95353585203567
101525143320017
1153889a709909
122076bb4b3b81
13b0a88550365
1453b62a7db69
1529a1492c097
hex16319a035d1

1525143320017 has 2 divisors, whose sum is σ = 1525143320018. Its totient is φ = 1525143320016.

The previous prime is 1525143319991. The next prime is 1525143320081. The reversal of 1525143320017 is 7100233415251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 767728192401 + 757415127616 = 876201^2 + 870296^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1525143320017 is a prime.

It is not a weakly prime, because it can be changed into another prime (1525143320087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 762571660008 + 762571660009.

It is an arithmetic number, because the mean of its divisors is an integer number (762571660009).

Almost surely, 21525143320017 is an apocalyptic number.

It is an amenable number.

1525143320017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1525143320017 is an equidigital number, since it uses as much as digits as its factorization.

1525143320017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25200, while the sum is 34.

Adding to 1525143320017 its reverse (7100233415251), we get a palindrome (8625376735268).

The spelling of 1525143320017 in words is "one trillion, five hundred twenty-five billion, one hundred forty-three million, three hundred twenty thousand, seventeen".