15253113121 has 4 divisors (see below), whose sum is σ = 15332972544. Its totient is φ = 15173253700.

The previous prime is 15253113097. The next prime is 15253113143. The reversal of 15253113121 is 12131135251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12131135251 = 34939 ⋅347209.

It is a cyclic number.

It is not a de Polignac number, because 15253113121 - 2¹¹ = 15253111073 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15253113221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39929425 + ... + 39929806.

It is an arithmetic number, because the mean of its divisors is an integer number (3833243136).

Almost surely, 2^15253113121 is an apocalyptic number.

It is an amenable number.

15253113121 is a deficient number, since it is larger than the sum of its proper divisors (79859423).

15253113121 is an equidigital number, since it uses as much as digits as its factorization.

15253113121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79859422.

The product of its digits is 900, while the sum is 25.

Adding to 15253113121 its reverse (12131135251), we get a palindrome (27384248372).

The spelling of 15253113121 in words is "fifteen billion, two hundred fifty-three million, one hundred thirteen thousand, one hundred twenty-one".