Search a number
-
+
152544113 is a prime number
BaseRepresentation
bin10010001011110…
…10001101110001
3101122001001011222
421011322031301
5303022402423
623045314425
73531414011
oct1105721561
9348031158
10152544113
117911a717
1243105a15
13257acbb7
141638bc41
15d5d33c8
hex917a371

152544113 has 2 divisors, whose sum is σ = 152544114. Its totient is φ = 152544112.

The previous prime is 152544107. The next prime is 152544137. The reversal of 152544113 is 311445251.

152544113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78446449 + 74097664 = 8857^2 + 8608^2 .

It is a cyclic number.

It is not a de Polignac number, because 152544113 - 24 = 152544097 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (152544173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76272056 + 76272057.

It is an arithmetic number, because the mean of its divisors is an integer number (76272057).

Almost surely, 2152544113 is an apocalyptic number.

It is an amenable number.

152544113 is a deficient number, since it is larger than the sum of its proper divisors (1).

152544113 is an equidigital number, since it uses as much as digits as its factorization.

152544113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2400, while the sum is 26.

The square root of 152544113 is about 12350.8749892467. The cubic root of 152544113 is about 534.3163749190.

Adding to 152544113 its reverse (311445251), we get a palindrome (463989364).

The spelling of 152544113 in words is "one hundred fifty-two million, five hundred forty-four thousand, one hundred thirteen".