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15255120131 is a prime number
BaseRepresentation
bin11100011010100011…
…01010100100000011
31110101011012101201022
432031101222210003
5222220302321011
611001430100055
71050015244616
oct161521524403
943334171638
1015255120131
1165191325a9
122b58aaa62b
131591662104
14a4a07417d
155e440a8db
hex38d46a903

15255120131 has 2 divisors, whose sum is σ = 15255120132. Its totient is φ = 15255120130.

The previous prime is 15255120107. The next prime is 15255120151. The reversal of 15255120131 is 13102155251.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15255120131 is a prime.

It is a super-2 number, since 2×152551201312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 15255120131.

It is not a weakly prime, because it can be changed into another prime (15255120151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7627560065 + 7627560066.

It is an arithmetic number, because the mean of its divisors is an integer number (7627560066).

Almost surely, 215255120131 is an apocalyptic number.

15255120131 is a deficient number, since it is larger than the sum of its proper divisors (1).

15255120131 is an equidigital number, since it uses as much as digits as its factorization.

15255120131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1500, while the sum is 26.

Adding to 15255120131 its reverse (13102155251), we get a palindrome (28357275382).

It can be divided in two parts, 15255120 and 131, that added together give a palindrome (15255251).

The spelling of 15255120131 in words is "fifteen billion, two hundred fifty-five million, one hundred twenty thousand, one hundred thirty-one".