Base | Representation |
---|---|
bin | 11100011010100011… |
… | …01100111111000001 |
3 | 1110101011012220022122 |
4 | 32031101230333001 |
5 | 222220303130144 |
6 | 11001430214025 |
7 | 1050015315545 |
oct | 161521547701 |
9 | 43334186278 |
10 | 15255130049 |
11 | 6519139aa5 |
12 | 2b58ab4315 |
13 | 1591666793 |
14 | a4a077a25 |
15 | 5e440d7ee |
hex | 38d46cfc1 |
15255130049 has 2 divisors, whose sum is σ = 15255130050. Its totient is φ = 15255130048.
The previous prime is 15255130031. The next prime is 15255130057. The reversal of 15255130049 is 94003155251.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9829334449 + 5425795600 = 99143^2 + 73660^2 .
It is a cyclic number.
It is not a de Polignac number, because 15255130049 - 232 = 10960162753 is a prime.
It is not a weakly prime, because it can be changed into another prime (15255150049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7627565024 + 7627565025.
It is an arithmetic number, because the mean of its divisors is an integer number (7627565025).
Almost surely, 215255130049 is an apocalyptic number.
It is an amenable number.
15255130049 is a deficient number, since it is larger than the sum of its proper divisors (1).
15255130049 is an equidigital number, since it uses as much as digits as its factorization.
15255130049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 35.
The spelling of 15255130049 in words is "fifteen billion, two hundred fifty-five million, one hundred thirty thousand, forty-nine".
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