Base | Representation |
---|---|
bin | 1000111000010100001… |
… | …0110010111110110001 |
3 | 112120202212221122100211 |
4 | 2032011002302332301 |
5 | 4444413311130233 |
6 | 154025551344121 |
7 | 14010323151262 |
oct | 2160502627661 |
9 | 476685848324 |
10 | 152555958193 |
11 | 597759523a1 |
12 | 25696822041 |
13 | 11502c71c62 |
14 | 755300a969 |
15 | 3e7d1b05cd |
hex | 23850b2fb1 |
152555958193 has 2 divisors, whose sum is σ = 152555958194. Its totient is φ = 152555958192.
The previous prime is 152555958173. The next prime is 152555958301. The reversal of 152555958193 is 391859555251.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 147757209664 + 4798748529 = 384392^2 + 69273^2 .
It is an emirp because it is prime and its reverse (391859555251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 152555958193 - 25 = 152555958161 is a prime.
It is not a weakly prime, because it can be changed into another prime (152555958173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76277979096 + 76277979097.
It is an arithmetic number, because the mean of its divisors is an integer number (76277979097).
Almost surely, 2152555958193 is an apocalyptic number.
It is an amenable number.
152555958193 is a deficient number, since it is larger than the sum of its proper divisors (1).
152555958193 is an equidigital number, since it uses as much as digits as its factorization.
152555958193 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12150000, while the sum is 58.
The spelling of 152555958193 in words is "one hundred fifty-two billion, five hundred fifty-five million, nine hundred fifty-eight thousand, one hundred ninety-three".
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