Base | Representation |
---|---|
bin | 1000111001111111000… |
… | …0010100100110101011 |
3 | 112121221010012121100221 |
4 | 2032133300110212223 |
5 | 10001323022200021 |
6 | 154142240510511 |
7 | 14024404251220 |
oct | 2163760244653 |
9 | 477833177327 |
10 | 153004100011 |
11 | 59985909a34 |
12 | 257a091b437 |
13 | 11574a6ac29 |
14 | 7596743947 |
15 | 3ea76d3241 |
hex | 239fc149ab |
153004100011 has 32 divisors (see below), whose sum is σ = 185650053120. Its totient is φ = 123175533600.
The previous prime is 153004100003. The next prime is 153004100027. The reversal of 153004100011 is 110001400351.
It is not a de Polignac number, because 153004100011 - 23 = 153004100003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (153001100011) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32614176 + ... + 32618866.
It is an arithmetic number, because the mean of its divisors is an integer number (5801564160).
Almost surely, 2153004100011 is an apocalyptic number.
153004100011 is a deficient number, since it is larger than the sum of its proper divisors (32645953109).
153004100011 is a wasteful number, since it uses less digits than its factorization.
153004100011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6775.
The product of its (nonzero) digits is 60, while the sum is 16.
Adding to 153004100011 its reverse (110001400351), we get a palindrome (263005500362).
The spelling of 153004100011 in words is "one hundred fifty-three billion, four million, one hundred thousand, eleven".
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