Base | Representation |
---|---|
bin | 1000111001111110010… |
… | …0111000001011101011 |
3 | 112121220220120012010211 |
4 | 2032133210320023223 |
5 | 10001321240200021 |
6 | 154142052321551 |
7 | 14024336614654 |
oct | 2163744701353 |
9 | 477826505124 |
10 | 153001100011 |
11 | 5998414aaa1 |
12 | 2579b9132b7 |
13 | 1157425a596 |
14 | 75961a252b |
15 | 3ea72de3e1 |
hex | 239f9382eb |
153001100011 has 2 divisors, whose sum is σ = 153001100012. Its totient is φ = 153001100010.
The previous prime is 153001100009. The next prime is 153001100023. The reversal of 153001100011 is 110001100351.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 153001100011 - 21 = 153001100009 is a prime.
Together with 153001100009, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 153001099964 and 153001100000.
It is not a weakly prime, because it can be changed into another prime (153001100081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76500550005 + 76500550006.
It is an arithmetic number, because the mean of its divisors is an integer number (76500550006).
Almost surely, 2153001100011 is an apocalyptic number.
153001100011 is a deficient number, since it is larger than the sum of its proper divisors (1).
153001100011 is an equidigital number, since it uses as much as digits as its factorization.
153001100011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15, while the sum is 13.
Adding to 153001100011 its reverse (110001100351), we get a palindrome (263002200362).
The spelling of 153001100011 in words is "one hundred fifty-three billion, one million, one hundred thousand, eleven".
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