Base | Representation |
---|---|
bin | 1000111001111111000… |
… | …0011100001100110011 |
3 | 112121221010021012001020 |
4 | 2032133300130030303 |
5 | 10001323024143443 |
6 | 154142241310523 |
7 | 14024404441014 |
oct | 2163760341463 |
9 | 477833235036 |
10 | 153004131123 |
11 | 59985930348 |
12 | 257a0935443 |
13 | 11574a7c13c |
14 | 759675100b |
15 | 3ea76dc583 |
hex | 239fc1c333 |
153004131123 has 8 divisors (see below), whose sum is σ = 210586331136. Its totient is φ = 98712342600.
The previous prime is 153004131097. The next prime is 153004131127. The reversal of 153004131123 is 321131400351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 153004131123 - 29 = 153004130611 is a prime.
It is a super-2 number, since 2×1530041311232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 153004131093 and 153004131102.
It is not an unprimeable number, because it can be changed into a prime (153004131127) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 822602763 + ... + 822602948.
It is an arithmetic number, because the mean of its divisors is an integer number (26323291392).
Almost surely, 2153004131123 is an apocalyptic number.
153004131123 is a deficient number, since it is larger than the sum of its proper divisors (57582200013).
153004131123 is a wasteful number, since it uses less digits than its factorization.
153004131123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1645205745.
The product of its (nonzero) digits is 1080, while the sum is 24.
Adding to 153004131123 its reverse (321131400351), we get a palindrome (474135531474).
The spelling of 153004131123 in words is "one hundred fifty-three billion, four million, one hundred thirty-one thousand, one hundred twenty-three".
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