Base | Representation |
---|---|
bin | 1101111010100110110011… |
… | …1001100111010101110011 |
3 | 2000011201021012011000220121 |
4 | 3132221230321213111303 |
5 | 4001140411120113102 |
6 | 52312541455151111 |
7 | 3136265444552416 |
oct | 336515471472563 |
9 | 60151235130817 |
10 | 15300500551027 |
11 | 49699a675020a |
12 | 187140a815497 |
13 | 86caa5967213 |
14 | 3ac7962b3b7d |
15 | 1b8003c49b37 |
hex | dea6ce67573 |
15300500551027 has 2 divisors, whose sum is σ = 15300500551028. Its totient is φ = 15300500551026.
The previous prime is 15300500551001. The next prime is 15300500551103. The reversal of 15300500551027 is 72015500500351.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15300500551027 is a prime.
It is a super-2 number, since 2×153005005510272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15300500550983 and 15300500551001.
It is not a weakly prime, because it can be changed into another prime (15300509551027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7650250275513 + 7650250275514.
It is an arithmetic number, because the mean of its divisors is an integer number (7650250275514).
Almost surely, 215300500551027 is an apocalyptic number.
15300500551027 is a deficient number, since it is larger than the sum of its proper divisors (1).
15300500551027 is an equidigital number, since it uses as much as digits as its factorization.
15300500551027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26250, while the sum is 34.
The spelling of 15300500551027 in words is "fifteen trillion, three hundred billion, five hundred million, five hundred fifty-one thousand, twenty-seven".
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