Base | Representation |
---|---|
bin | 10110010001001111011… |
… | …011101010100001010001 |
3 | 12102022002002121010011202 |
4 | 112101033123222201101 |
5 | 200033114244300424 |
6 | 3131010130520545 |
7 | 215364163645115 |
oct | 26211733524121 |
9 | 5368062533152 |
10 | 1530341009489 |
11 | 540017670946 |
12 | 208710136155 |
13 | b1406337666 |
14 | 540d70c1745 |
15 | 29c1add32ae |
hex | 1644f6ea851 |
1530341009489 has 2 divisors, whose sum is σ = 1530341009490. Its totient is φ = 1530341009488.
The previous prime is 1530341009479. The next prime is 1530341009501. The reversal of 1530341009489 is 9849001430351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1366140192400 + 164200817089 = 1168820^2 + 405217^2 .
It is a cyclic number.
It is not a de Polignac number, because 1530341009489 - 240 = 430829381713 is a prime.
It is a super-2 number, since 2×15303410094892 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1530341009419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765170504744 + 765170504745.
It is an arithmetic number, because the mean of its divisors is an integer number (765170504745).
Almost surely, 21530341009489 is an apocalyptic number.
It is an amenable number.
1530341009489 is a deficient number, since it is larger than the sum of its proper divisors (1).
1530341009489 is an equidigital number, since it uses as much as digits as its factorization.
1530341009489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 47.
The spelling of 1530341009489 in words is "one trillion, five hundred thirty billion, three hundred forty-one million, nine thousand, four hundred eighty-nine".
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