Base | Representation |
---|---|
bin | 1101111010111001011110… |
… | …0100100101000010000100 |
3 | 2000012012012101222202120101 |
4 | 3132232113210211002010 |
5 | 4001231141411033012 |
6 | 52315131015413444 |
7 | 3136533561354046 |
oct | 336562744450204 |
9 | 60165171882511 |
10 | 15305511424132 |
11 | 4971038204356 |
12 | 1872388984284 |
13 | 8703c3b31ba7 |
14 | 3acb0d9a5a96 |
15 | 1b81e8aecd57 |
hex | deb97925084 |
15305511424132 has 24 divisors (see below), whose sum is σ = 27650297814272. Its totient is φ = 7405455477600.
The previous prime is 15305511424129. The next prime is 15305511424183. The reversal of 15305511424132 is 23142411550351.
It is a junction number, because it is equal to n+sod(n) for n = 15305511424091 and 15305511424100.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1528758 + ... + 5740045.
Almost surely, 215305511424132 is an apocalyptic number.
It is an amenable number.
15305511424132 is a deficient number, since it is larger than the sum of its proper divisors (12344786390140).
15305511424132 is a wasteful number, since it uses less digits than its factorization.
15305511424132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7285819 (or 7285817 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 15305511424132 its reverse (23142411550351), we get a palindrome (38447922974483).
The spelling of 15305511424132 in words is "fifteen trillion, three hundred five billion, five hundred eleven million, four hundred twenty-four thousand, one hundred thirty-two".
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