Base | Representation |
---|---|
bin | 11100100000100100… |
… | …00000001000011001 |
3 | 1110111200001222221100 |
4 | 32100102000020121 |
5 | 222321204240441 |
6 | 11010430502013 |
7 | 1051166641644 |
oct | 162022001031 |
9 | 43450058840 |
10 | 15305540121 |
11 | 654463a913 |
12 | 2b71964909 |
13 | 159bc36721 |
14 | a52a3aa5b |
15 | 5e8a69cb6 |
hex | 390480219 |
15305540121 has 24 divisors (see below), whose sum is σ = 22193373384. Its totient is φ = 10164349440.
The previous prime is 15305540119. The next prime is 15305540207. The reversal of 15305540121 is 12104550351.
15305540121 is a `hidden beast` number, since 1 + 530 + 5 + 5 + 4 + 0 + 121 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 2158624521 + 13146915600 = 46461^2 + 114660^2 .
It is not a de Polignac number, because 15305540121 - 21 = 15305540119 is a prime.
It is not an unprimeable number, because it can be changed into a prime (15305540111) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6492475 + ... + 6494831.
It is an arithmetic number, because the mean of its divisors is an integer number (924723891).
Almost surely, 215305540121 is an apocalyptic number.
It is an amenable number.
15305540121 is a deficient number, since it is larger than the sum of its proper divisors (6887833263).
15305540121 is a wasteful number, since it uses less digits than its factorization.
15305540121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4841 (or 4838 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 27.
The spelling of 15305540121 in words is "fifteen billion, three hundred five million, five hundred forty thousand, one hundred twenty-one".
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