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1531250000001 = 3356712962963
BaseRepresentation
bin10110010010000101100…
…111001100000010000001
312102101102110000121202000
4112102011213030002001
5200042000000000001
63131240241414213
7215425542150201
oct26220547140201
95371373017660
101531250000001
11540443783977
1220892463a369
13b151c75b277
1454181adc401
1529c70ad8a86
hex164859cc081

1531250000001 has 8 divisors (see below), whose sum is σ = 2268518518560. Its totient is φ = 1020833333316.

The previous prime is 1531249999999. The next prime is 1531250000009. The reversal of 1531250000001 is 1000000521351.

1531250000001 is a `hidden beast` number, since 153 + 12 + 500 + 0 + 0 + 0 + 0 + 1 = 666.

It is not a de Polignac number, because 1531250000001 - 21 = 1531249999999 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1531250000009) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28356481455 + ... + 28356481508.

It is an arithmetic number, because the mean of its divisors is an integer number (283564814820).

Almost surely, 21531250000001 is an apocalyptic number.

It is an amenable number.

1531250000001 is a deficient number, since it is larger than the sum of its proper divisors (737268518559).

1531250000001 is an equidigital number, since it uses as much as digits as its factorization.

1531250000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56712962972 (or 56712962966 counting only the distinct ones).

The product of its (nonzero) digits is 150, while the sum is 18.

Adding to 1531250000001 its reverse (1000000521351), we get a palindrome (2531250521352).

The spelling of 1531250000001 in words is "one trillion, five hundred thirty-one billion, two hundred fifty million, one", and thus it is an aban number.

Divisors: 1 3 9 27 56712962963 170138888889 510416666667 1531250000001